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Proof step 5 from proof shift-01 (previous step)

∀ m, n. m - n - n1 = m - n + n1 ⊦ m - n - n1 - 1 = m - n + n1 + 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ m - n + 1 = m - n - 1
Proof step 7:
∀ m, n. m - n - n1 = m - n + n1 ⊦ m - n - n1 - 1 = m - n1 + n - 1

Rule argument

spec: inst: name: rax seq: ⊦ m - n + 1 = m - n - 1 subst: [n, m] → [n1 + n, m] flags: rewrite, current

Additional information

Used simplifier rules: a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2 Used terms: n1 + n, m