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Proof step 1 from proof sub-le-rew (conclusion)

m0 ≤ m, n0 ≤ n ⊦ m - m0 ≤ n - n0 ↔ m + n0 ≤ n + m0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
m0 ≤ m, n0 ≤ n ⊦ m ≤ (n - n0) + m0 ↔ m + n0 ≤ n + m0

Rule argument

Additional information

Used simplifier rules: lels-01: ⊦ ¬ m ≤ n ↔ n < m;%le-ls-simp: ⊦ m ≤ n → (n < m ↔ false);%ls-03: n0 ≤ n ⊦ n - n0 ≤ m ↔ n ≤ m + n0;