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Proof step 1 from proof loc (conclusion)
⊦ ¬ a < b ↔ ¬ ¬(a = b ∨ b < a)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
⊦ ¬ a < b ↔ a = b ∨ b < a
Rule argument
Additional information