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Proof step 22 from proof ins-max (previous step)

ordered≤(max(x) ' + x), ∀ a1. ins≤(a1, x) = x + a1 ' ∨ a1 < max(x) ⊦ max(x) ' + x = x + max(x) ', x = []

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: max(x)

Additional information

Used simplifier rules: a: ⊦ (x + y) + z = x + y + z; from specification list%cons-03: ⊦ ordered≤(a ' + x) → ins≤(a, x) = a ' + x; from specification olist%irreflexivity: ⊦ ¬ a < a; from specification oelem Used terms: max(x)