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Proof step 16 from proof max-append (previous step)

x1 ≠ [], ∀ x0. max(x1 + x0) = max(x1) ∨ max(x1 + x0) = max(x0) ∨ x1 + x0 = [] ⊦ x1 + x0 = [], max(x1 + x0) = (max(x1) < a ⊃ a;max(x1)), max(x1 + x0) = max(x0), max(x1 + x0) < a

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
∀ x0. max(x1 + x0) = max(x1) ∨ max(x1 + x0) = max(x0) ∨ x1 + x0 = [] ⊦ x1 + x0 = [], max(x1 + x0) = (max(x1) < a ⊃ a;max(x1)), max(x1 + x0) = max(x0), x1 = [], max(x1 + x0) < a

Proof step 16 from proof max-append (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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