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Proof step 8 from proof max-append (previous step)

max(x1 + x0) < a, ∀ x0. max(x1 + x0) = max(x1) ∨ max(x1 + x0) = max(x0) ∨ x1 + x0 = [] ⊦ a = max(a ' + x1), (max(x1 + x0) < a ⊃ a;max(x1 + x0)) = max(x0), x1 + x0 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
max(x1 + x0) < a, ∀ x0. max(x1 + x0) = max(x1) ∨ max(x1 + x0) = max(x0) ∨ x1 + x0 = [] ⊦ x1 + x0 = [], a = max(a ' + x1), a = max(x0)

Proof step 8 from proof max-append (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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