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Proof step 23 from proof max-com (previous step)

∀ x1, x2. # x1 + # x2 < #(a + []) + #(a0 + []) → true → x1 + x2 = [] ∨ max(x1 + x2) = max(x2 + x1) ⊦ a0 = (a < a0 ⊃ a0;a), a0 < a

User applied rule case distinction

And closed the goal!

Rule argument

pos: right 1

Additional information

Used simplifier rules: seq: ⊦ ¬ b < a → (¬ a < b ↔ a = b); from specification oelem