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Proof step 8 from proof max-com (previous step)

x3 + x0 ≠ [], ∀ x1, x2. # x1 + # x2 < #(a + x3) + # x0 → true → x1 + x2 = [] ∨ max(x1 + x2) = max(x2 + x1) ⊦ (max(x3 + x0) < a ⊃ a;max(x3 + x0)) = max(x0 + a ' + x3)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
∀ x1, x2. # x1 + # x2 < #(a + x3) + # x0 → true → x1 + x2 = [] ∨ max(x1 + x2) = max(x2 + x1) ⊦ (max(x3 + x0) < a ⊃ a;max(x3 + x0)) = max(x0 + a ' + x3), x3 + x0 = []

Proof step 8 from proof max-com (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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