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Proof step 2 from proof max-ge-01 (previous step)

(max(x) < a ⊃ a;max(x)) < max(x) ⊦ x = []

Heuristic if-then-else split applied rule case distinction

And closed the goal!

Rule argument

pos: left 1

Additional information

Used simplifier rules: irreflexivity: ⊦ ¬ a < a; from specification oelem%transitivity: ⊦ a < b ∧ b < c → a < c; (forward) from specification oelem