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Proof step 17 from proof max-ge (
previous step
)
max(x1 + x0) < max(x1), a < max(x1) ⊦ x1 = [], x1 + x0 = [], max(x1 + x0) < a, ∃ x0. max(x1 + x0) < max(x1)
Heuristic quantifier closing applied rule exists right
And closed the goal!
Rule argument
pos: right 4 terms: x0
Additional information
Used terms: x0