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Proof step 20 from proof max-ins-last (previous step)

ins≤(a, x0) ≠ [], a0 < a, max(x0) < a, ∀ a. max(x0) < a → ins≤(a, x0).last = a ⊦ x0 = [], ins≤(a, x0).last = a, max(x0) < a0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
a0 < a, max(x0) < a, ∀ a. max(x0) < a → ins≤(a, x0).last = a ⊦ x0 = [], ins≤(a, x0).last = a, max(x0) < a0

Rule argument

Additional information

Used simplifier rules: empty: ⊦ ins≤(a, x) ≠ []; from specification olist