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Proof step 6 from proof max-ins-last (previous step)

x0 ≠ [], (max(x0) < a0 ⊃ a0;max(x0)) < a, ∀ a. max(x0) < a → ins≤(a, x0).last = a ⊦ ins≤(a, a0 ' + x0).last = a

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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