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Proof step 16 from proof max-ins-max (previous step)

max(ins≤(a, x0)) < a0, a0 < a, ∀ a. max(ins≤(a, x0)) = a ∨ a < max(x0) ⊦ (max(ins≤(a, x0)) < a0 ⊃ a0;max(ins≤(a, x0))) = a, a < max(a0 ' + x0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
max(ins≤(a, x0)) < a0, a0 < a, max(ins≤(a, x0)) < a, ∀ a. max(ins≤(a, x0)) = a ∨ a < max(x0) ⊦ a0 = a, a < max(a0 ' + x0)

Rule argument

Additional information

Used simplifier rules: transitivity: ⊦ a < b ∧ b < c → a < c; (forward) from specification oelem