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Proof step 19 from proof max-ins-max (previous step)

¬ ordered≤(a ' + x0), max(ins≤(a, x0)) < a0, a0 < a, max(ins≤(a, x0)) < a, ∀ a. max(ins≤(a, x0)) = a ∨ a < max(x0) ⊦ a0 = a, a < max(a0 ' + x0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information