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Proof step 36 from proof max-ins-max (previous step)

ordered≤(a ' + a0 ' + x0), ∀ a. max(ins≤(a, x0)) = a ∨ a < max(x0) ⊦ max(a ' + a0 ' + x0) = a, a < max(a0 ' + x0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 37:
ordered≤(a0 ' + x0), ∀ a. max(ins≤(a, x0)) = a ∨ a < max(x0) ⊦ max(a ' + a0 ' + x0) = a, a < max(a0 ' + x0), a0 < a, a0 < max(a0 ' + x0)

Rule argument

Additional information

Used simplifier rules: nnn: ⊦ ¬ c < b ∧ ¬ a < c → ¬ a < b; (forward) from specification oelem%a: ⊦ (x + y) + z = x + y + z; from specification list%c: ⊦ a + x = a ' + x; from specification list%le-r: ⊦ ordered≤(a ' + b ' + x) ↔ ¬ b < a ∧ ordered≤(b + x); from specification olist