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Proof step 27 from proof max-ins (previous step)

a0 < a, ∀ a1. max(ins≤(a1, x0)) = max(x0) ∨ max(x0) < a1 ⊦ x0 = [], max(ins≤(a, x0)) = max(x0), max(ins≤(a, x0)) < a0, max(x0) < a0, max(x0) < a

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: a

Additional information

Used terms: a