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Proof step 1 from proof max-ordered (conclusion)
⊦ x ≠ [] ∧ max(x + x0) = max(x) ∧ ordered≤(x0) ∧ x1 ⊑ x0 → (max(x + x1) ≠ max(x + x0) ↔ false)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
max(x + x0) = max(x), ordered≤(x0), x1 ⊑ x0 ⊦ x = [], max(x + x1) = max(x)
Rule argument
Additional information