[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 34 from proof max-ordered (previous step)

max((a ' + x2) + x0) = a, max(x2) < max(x2 + x1), a < max(x2 + x1), x1 ⊑ x0, ordered≤(x0), max(x2) < a, ∀ x, x3. max(x2 + x) = max(x2) ∧ ordered≤(x) ∧ x3 ⊑ x → max(x2 + x3) = max(x2) ⊦ x2 = [], x2 + x1 = [], max(x2 + x1) = a

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 35:
⊦ x ≠ [] → max(a ' + x) = (max(x) < a ⊃ a;max(x))
Proof step 36:
x2 + x0 ≠ [], (max(x2 + x0) < a ⊃ a;max(x2 + x0)) = a, max(x2) < max(x2 + x1), a < max(x2 + x1), x1 ⊑ x0, ordered≤(x0), max(x2) < a, ∀ x, x3. max(x2 + x) = max(x2) ∧ ordered≤(x) ∧ x3 ⊑ x → max(x2 + x3) = max(x2) ⊦ x2 = [], x2 + x1 = [], max(x2 + x1) = a

Rule argument

spec: inst: name: max-rec seq: ⊦ x ≠ [] → max(a ' + x) = (max(x) < a ⊃ a;max(x)) subst: [x, a] → [x2 + x0, a] flags: rewrite, current

Additional information

Used simplifier rules: app-02-ant: ⊦ ¬ x + y ≠ [] ↔ x = [] ∧ y = []; from specification list%a: ⊦ (x + y) + z = x + y + z; from specification list Used terms: x2 + x0, a