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Proof step 20 from proof max-sort-sublist (previous step)

x1 ≠ [], max(x1 + x0) = max(x0), max(x0) < a, ∀ x0. x1 + x0 = [] ∨ max(x1 + x0) = max(x1) ∨ max(x1 + x0) = max(x0) ⊦ a = (max(x1) < a ⊃ a;max(x1)), a = max(x0), x1 + x0 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
max(x1 + x0) = max(x0), max(x0) < a, ∀ x0. x1 + x0 = [] ∨ max(x1 + x0) = max(x1) ∨ max(x1 + x0) = max(x0) ⊦ a = (max(x1) < a ⊃ a;max(x1)), a = max(x0), x1 + x0 = [], x1 = []

Proof step 20 from proof max-sort-sublist (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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