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Proof step 28 from proof max-sort-sublist (previous step)

max(x1) < a, a < max(x1 + x0), max(x1) < max(x1 + x0), ∀ x0. x1 + x0 = [] ∨ max(x1 + x0) = max(x1) ∨ max(x1 + x0) = max(x0) ⊦ max(x1 + x0) = a, x1 + x0 = [], max(x1 + x0) = max(x0), x1 = []

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: x0

Additional information

Used simplifier rules: max-ge: ⊦ x ≠ [] → (¬ ¬ max(x + x0) < max(x) ↔ false);%transitivity: ⊦ a < b ∧ b < c → a < c; (forward) from specification oelem%lel: ⊦ a < b ∧ a = c → c < b; (forward) from specification oelem%a: ⊦ (x + y) + z = x + y + z; from specification list Used terms: x0