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Proof step 30 from proof max-sort-sublist (previous step)

∀ x0. x1 + x0 = [] ∨ max(x1 + x0) = max(x1) ∨ max(x1 + x0) = max(x0) ⊦ max(x1 + x0) = max(x1), x1 + x0 = [], max(x1 + x0) = max(x0), x1 = [], max(x1 + x0) < a, max(x1) < a

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: x0

Additional information

Used terms: x0