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Proof step 4 from proof max-sort-sublist (previous step)

∀ x0. x1 + x0 = [] ∨ max(x1 + x0) = max(x1) ∨ max(x1 + x0) = max(x0) ⊦ max((a ' + x1) + x0) = max(a ' + x1), max((a ' + x1) + x0) = max(x0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ (a ' + x) + y = a ' + x + y
Proof step 6:
∀ x0. x1 + x0 = [] ∨ max(x1 + x0) = max(x1) ∨ max(x1 + x0) = max(x0) ⊦ max(a ' + x1 + x0) = max(a ' + x1), max(a ' + x1 + x0) = max(x0)

Rule argument

spec: list inst: name: Noassoc seq: ⊦ (a ' + x) + y = a ' + x + y subst: [y, x, a] → [x0, x1, a] flags: rewrite

Additional information

Used terms: x0, x1, a