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Proof step 14 from proof sort-max-last (previous step)

sort(x1 + a ' + x0) = sort(x1 + x0) + a ' ⊦ ins≤(a, sort(x1 + x0) + a ') = (sort(x1 + x0) + a ') + a ', a < max((a ' + x1) + x0), a < max(x1 + x0), ordered≤(sort(x1 + x0) + a ') ∧ ¬ a < max(sort(x1 + x0) + a ')

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 15:
ordered≤(sort(x1 + x0) + a '), sort(x1 + a ' + x0) = sort(x1 + x0) + a ' ⊦ ins≤(a, sort(x1 + x0) + a ') = (sort(x1 + x0) + a ') + a ', a < max((a ' + x1) + x0), a < max(x1 + x0), ordered≤(sort(x1 + x0) + a ') ∧ ¬ a < max(sort(x1 + x0) + a ')
Proof step 23:
sort(x1 + a ' + x0) = sort(x1 + x0) + a ' ⊦ ordered≤(sort(x1 + x0) + a '), ins≤(a, sort(x1 + x0) + a ') = (sort(x1 + x0) + a ') + a ', a < max((a ' + x1) + x0), a < max(x1 + x0), ordered≤(sort(x1 + x0) + a ') ∧ ¬ a < max(sort(x1 + x0) + a ')

Rule argument

fma: ordered≤(sort(x1 + x0) + a ')

Additional information

Used formulas: ordered≤(sort(x1 + x0) + a ')