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Proof step 5 from proof sort-max-last (previous step)

a < max(x1 + x0), ¬ a < max(x1 + x0) → sort(x1 + a ' + x0) = sort(x1 + x0) + a ' ⊦ ins≤(a0, sort(x1 + a ' + x0)) = ins≤(a0, sort(x1 + x0)) + a ', a < max((a0 ' + x1) + x0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
a < max(x1 + x0), max((a0 ' + x1) + x0) < max(x1 + x0) ⊦ ins≤(a0, sort(x1 + a ' + x0)) = ins≤(a0, sort(x1 + x0)) + a ', a < max((a0 ' + x1) + x0)

Rule argument

Additional information

Used simplifier rules: nll: ⊦ ¬ b < a ∧ b < c → a < c; (forward) from specification oelem