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Proof step 4 from proof sort-max-max-list (previous step)

max(sort(x0)) = max(x0) ⊦ x0 = [], max(ins≤(a, sort(x0))) = (max(x0) < a ⊃ a;max(x0))

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 5:
max(x0) < a, max(sort(x0)) = max(x0) ⊦ max(ins≤(a, sort(x0))) = a, x0 = []
Proof step 17:
¬ max(x0) < a, max(sort(x0)) = max(x0) ⊦ max(ins≤(a, sort(x0))) = max(x0), x0 = []

Rule argument

pos: right 2

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