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Proof step 1 from proof sort-max (conclusion)

⊦ x ≠ [] → max(sort(x)) = sort(x).last

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ x ≠ [] ∧ ordered≤(x) → max(x) = x.last

Rule argument

spec: inst: name: ordered-max seq: ⊦ x ≠ [] ∧ ordered≤(x) → max(x) = x.last subst: [x] → [sort(x)] flags: rewrite, current

Additional information

Used simplifier rules: sort-max-max-list: ⊦ x ≠ [] → max(sort(x)) = max(x);%emptyp: ⊦ sort(x) = [] ↔ x = []; from specification olist-sort%Ordered: ⊦ ordered≤(sort(x)); from specification olist-sort Used terms: sort(x)