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Proof step 7 from proof del1 (previous step)

sort(x0 -1l a) = sort(x0) -1l a ⊦ a = a0, ins≤(a0, sort(x0 -1l a)) = ins≤(a0, sort(x0)) -1l a

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
sort(x0 -1l a) = sort(x0) -1l a ⊦ a = a0, ins≤(a0, sort(x0) -1l a) = ins≤(a0, sort(x0)) -1l a

Rule argument

Additional information