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Proof step 4 from proof app-02 (previous step)

ordered≤((a ' + x0) + y + z), ∀ y, z. ordered≤(x0 + y + z) → ordered≤(y) ⊦ ordered≤(y)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: y, z

Additional information

Used simplifier rules: app-01: ⊦ ordered≤(x + y) → ordered≤(y);%a: ⊦ (x + y) + z = x + y + z; from specification list Used terms: y, z