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Proof step 9 from proof app (
previous step
)
ordered≤(a0 ' + y0 + y) ⊦ ordered≤(a0 ' + y0), a0 < a, ∃ y1. ordered≤((a0 ' + y0) + y1)
Heuristic quantifier closing applied rule exists right
And closed the goal!
Rule argument
pos: right 3 terms: y
Additional information
Used simplifier rules: a: ⊦ (x + y) + z = x + y + z; from specification list Used terms: y