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Proof step 1 from proof del1-01-01 (conclusion)

⊦ ordered≤(a ' + (x -1l a)) ∧ ordered≤(x) ∧ a ∈ x → a ' + (x -1l a) = x

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
a ∈ x, ordered≤(x), ordered≤(a ' + (x -1l a)) ⊦ a ' + (x -1l a) = x

Rule argument

Additional information

Used simplifier rules: cons-02: ⊦ ordered≤(a ' + x) → ordered≤(x);%del1-01: ⊦ ordered≤(x) → ordered≤(x -1l a);%a: ⊦ (x + y) + z = x + y + z; from specification list