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Proof step 17 from proof del1-01 (previous step)

(a2 ' + y) -1l a = a3 ' + y0, ordered≤(a2 ' + y), ∀ a1. ordered≤((a2 ' + y) -1l a1) ⊦ a = a0, a2 < a0, ¬ a3 < a0 ∧ ordered≤(a3 ' + y0)

User applied rule all left

And obtained the following new goals

Proof step 18:
(a2 ' + y) -1l a = a3 ' + y0, ordered≤(a2 ' + y), ordered≤((a2 ' + y) -1l a), ∀ a1. ordered≤((a2 ' + y) -1l a1) ⊦ a = a0, a2 < a0, ¬ a3 < a0 ∧ ordered≤(a3 ' + y0)

Rule argument

pos: left 3 terms: a abort: F discard: F computed: T

Additional information

Used terms: a