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Proof step 6 from proof del1-01 (previous step)

a ≠ a0, ordered≤(a0 ' + x0), ∀ a1. ordered≤(x0 -1l a1) ⊦ ordered≤(a0 ' + (x0 -1l a))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information