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Proof step 12 from proof del1 (previous step)

x0 -1l a = a2 ' + y, a2 ∈ x0 -1l a, ordered<(a0 ' + x0), a2 ∈ x0, ∀ a1. ordered<(x0 -1l a1) ⊦ x0 -1l a = [], a = a0, a0 < a2 ∧ ordered<(x0 -1l a)

User applied rule all left

And obtained the following new goals

Proof step 13:
x0 -1l a = a2 ' + y, a2 ∈ x0 -1l a, ordered<(a0 ' + x0), a2 ∈ x0, ordered<(x0 -1l a) ⊦ x0 -1l a = [], a = a0, a0 < a2 ∧ ordered<(x0 -1l a)

Rule argument

pos: left 5 terms: a abort: F discard: T computed: T

Additional information

Used terms: a