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Proof step 3 from proof del1 (previous step)

∀ a. ordered<(x0) → ordered<(x0 -1l a), ordered<(a0 + x0) ⊦ ordered<((a0 + x0) -1l a)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: cons: ⊦ ordered<(a ' + x) → ordered<(x);%a: ⊦ (x + y) + z = x + y + z; from specification list%c: ⊦ a + x = a ' + x; from specification list