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Proof step 3 from proof empty (previous step)

∀ a. ins≤(a, x0) ≠ [], ins≤(a, a0 + x0) = [] ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
ins≤(a, a0 ' + x0) = [], ∀ a. ins≤(a, x0) ≠ [] ⊦

Rule argument

Additional information

Used simplifier rules: c: ⊦ a + x = a ' + x; from specification list