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Proof step 2 from proof ins2 (previous step)

⊦ ins≤(a, ins≤(b, x)) = ins≤(b, ins≤(a, x))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ ins≤(a, ins≤(b, x)) = ins≤(b, ins≤(a, x))

Rule argument

spec: olist inst: name: sw seq: ⊦ ins≤(a, ins≤(b, x)) = ins≤(b, ins≤(a, x)) subst: [x, b, a] → [x, b, a] flags: rewrite, current

Additional information

Used terms: x, b, a