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Proof step 4 from proof ole-in (previous step)

b ∈ x0, ordered≤(a0 ' + x0), b < a, ∀ b0, a1. ¬ b0 ∈ x0 ∨ ¬ ordered≤(a1 ' + x0) ∨ ¬ b0 < a1 ⊦ a0 < a

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: b, a0

Additional information

Used simplifier rules: nll: ⊦ ¬ b < a ∧ b < c → a < c; (forward) from specification oelem%nnn: ⊦ ¬ c < b ∧ ¬ a < c → ¬ a < b; (forward) from specification oelem Used terms: b, a0