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Proof step 24 from proof ole-last (previous step)

a0 < a2, a1 < a2, ordered≤(a1 ' + y0 + a2 '), ∀ a, b. ordered≤((a1 ' + y0) + a ') → (ordered≤((a1 ' + y0) + a ' + b ') ↔ ¬ b < a) ⊦ a1 = a2, a1 < a0, b < a1, b < a0, b < a2, ordered≤(a1 ' + y0 + a2 ' + b ')

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: a2, b

Additional information

Used simplifier rules: a: ⊦ (x + y) + z = x + y + z; from specification list Used terms: a2, b