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Proof step 6 from proof ole-last (previous step)

ordered≤((a0 ' + x0) + a ' + b '), b < a, ∀ a, b. ordered≤(x0 + a ') → (ordered≤(x0 + a ' + b ') ↔ ¬ b < a) ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: a, b

Additional information

Used simplifier rules: app-02: ⊦ ordered≤(x + y + z) → ordered≤(y);%app-01: ⊦ ordered≤(x + y) → ordered≤(y);%a: ⊦ (x + y) + z = x + y + z; from specification list Used terms: a, b