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Proof step 1 from proof ordered-append (conclusion)

⊦ ordered≤(x) ∧ ordered≤(x0) ∧ (x ≠ [] ∧ x0 ≠ [] → ¬ x0.first < x.last) → ordered≤(x + x0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information