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Proof step 20 from proof ordered-ex-divide-lels (previous step)

ordered≤(a0 ' + y + z), a < b, b ∈ y, ∀ b. b ∈ z → a < b, ∀ b. b ∈ y → b < a ∨ b = a ⊦ b = a0, b = a, ∃ y0, z0. a0 ' + y + z = y0 + z0 ∧ (∀ b. b ∈ y0 → b < a ∨ b = a) ∧ (∀ b. b ∈ z0 → a < b)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: b

Additional information

Used simplifier rules: transitivity: ⊦ a < b ∧ b < c → a < c; (forward) from specification oelem%irreflexivity: ⊦ ¬ a < a; from specification oelem Used terms: b