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Proof step 9 from proof ordered-ex-divide-lsle (previous step)

ordered≤(a0 ' + y + z), ∀ b. b ∈ z → b = a ∨ a < b, ∀ b. b ∈ y → b < a, b = a0 ∨ b ∈ y ⊦ b < a, ∃ y0, z0. a0 ' + y + z = y0 + z0 ∧ (∀ b. b ∈ y0 → b < a) ∧ (∀ b. b ∈ z0 → b = a ∨ a < b)

User applied rule cut formula

And obtained the following new goals

Proof step 10:
b = a0, ordered≤(a0 ' + y + z), ∀ b. b ∈ z → b = a ∨ a < b, ∀ b. b ∈ y → b < a, b = a0 ∨ b ∈ y ⊦ b < a, ∃ y0, z0. a0 ' + y + z = y0 + z0 ∧ (∀ b. b ∈ y0 → b < a) ∧ (∀ b. b ∈ z0 → b = a ∨ a < b)
Proof step 15:
ordered≤(a0 ' + y + z), ∀ b. b ∈ z → b = a ∨ a < b, ∀ b. b ∈ y → b < a, b = a0 ∨ b ∈ y ⊦ b = a0, b < a, ∃ y0, z0. a0 ' + y + z = y0 + z0 ∧ (∀ b. b ∈ y0 → b < a) ∧ (∀ b. b ∈ z0 → b = a ∨ a < b)

Rule argument

fma: b = a0

Additional information

Used formulas: b = a0