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Proof step 6 from proof ordered-postfix (previous step)

¬(a ' + x1 ≠ [] ∧ (a ' + x1).rest ≠ []), ordered≤(a ' + x1), x ⊒ a ' + x1, ∀ x0. x0 ⊒ x1 → ordered≤(x0) ⊦ ordered≤(x)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: le-o: ⊦ ordered≤(a ');%le-e: ⊦ ordered≤([]);%postfix-empty-03: ⊦ x ⊒ [] ↔ x = []; from specification list-last%app: ⊦ x + [] = x; from specification list%c-07: ⊦ (a ' + x).rest = x; from specification list%a: ⊦ (x + y) + z = x + y + z; from specification list%e-01: ⊦ a ' + x ≠ []; from specification list