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Proof step 34 from proof orderedle-all (previous step)

a0 < a, ordered≤(a0 ' + y), ∀ m, n. m ≤ n ∧ ¬ 1 + # y < n → ¬ (a ' + a0 ' + y)[n] < (a ' + a0 ' + y)[m], ∀ m, n. m ≤ n ∧ n < 1 + # y → ¬ (a0 ' + y)[n] < (a0 ' + y)[m] ⊦

User applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: 0, 1 abort: F discard: F computed: F

Additional information

Used simplifier rules: l-02: ⊦ ¬ m + n < m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2%get-numrec: n ≠ 0 ⊦ (a ' + x)[(* n)] = x[n -1]; from specification list-del%get-zero-01: ⊦ (a ' + x)[0] = a; from specification list-del%a: ⊦ (x + y) + z = x + y + z; from specification list Used terms: 0, 1