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Proof step 27 from proof orderedls-all (previous step)

a ' + a0 ' + y ≠ [] ∧ n ≠ 0, m1 + 1 < n, a < a0, ordered<(a0 ' + y), n ≤ 1 + # y, m1 < # y, ∀ m0, n0. m0 < n0 ∧ ¬ # y < n0 → (a0 ' + y)[m0] < (a0 ' + y)[n0] ⊦ y = [], (a0 ' + y)[m1] < (a ' + a0 ' + y).rest[n - 1]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: c-07: ⊦ (a ' + x).rest = x; from specification list%a: ⊦ (x + y) + z = x + y + z; from specification list%e-01: ⊦ a ' + x ≠ []; from specification list%f: ⊦ m < n → n ≠ 0; from specification nat-basic1