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Proof step 1 from proof bmin-del-02 (conclusion)

⊦ s ≠ ∅ → s -- a -- s.min = s.butmin -- a

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: Butmin: ⊦ s ≠ ∅ → s.butmin = s -- s.min;%delsw-02: ⊦ s -- b -- a = s -- a -- b ↔ true; from specification set-union