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Proof step 2 from proof bmin-del-04 (previous step)

s.min ∈ s, s.max ∈ s ⊦ a = s.min, s = ∅, (s -- a).butmin = s -- s.min -- a, # s = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ s -- b -- a = s -- a -- b
Proof step 4:
s.min ∈ s, s.max ∈ s ⊦ a = s.min, s = ∅, (s -- a).butmin = s -- a -- s.min, # s = 0

Rule argument

spec: set-union inst: name: delsw-01 seq: ⊦ s -- b -- a = s -- a -- b subst: [b, a, s] → [a, s.min, s] flags: rewrite

Additional information

Used terms: a, s.min, s