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Proof step 1 from proof bmin-del (conclusion)

⊦ s ≠ ∅ → s.butmin -- s.min = s.butmin

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: Butmin: ⊦ s ≠ ∅ → s.butmin = s -- s.min;%del-d: ⊦ s -- a -- a = s -- a; from specification set-union