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Proof step 5 from proof bmin-two-07 (previous step)
| (∅ ++ a ++ b).butmin = ∅ ⊦ a = b |
Heuristic weak cut applied rule cut formula
And closed the goal!
Rule argument
fma: b < aAdditional information
Used simplifier rules:
bmin-two-02: ⊦ a < b → (∅ ++ b ++ a).butmin = ∅ ++ b;%bmin-two-01: ⊦ a < b → (∅ ++ a ++ b).butmin = ∅ ++ b;%sls: ⊦ a ≠ b → (¬ a < b ↔ b < a); from specification oelem%ne: ⊦ ∅ ≠ s ++ a; from specification set-basic
Used formulas: b < a