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Proof step 4 from proof max-del (previous step)

¬ (s -- a).max ∈ s, s.max < (s -- a).max ⊦ s = ∅ ++ a

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
s.max < (s -- a).max ⊦ s = ∅ ++ a, (s -- a).max ∈ s

Rule argument

Additional information